What is limit of
cos(x)/((e^x)-1+1)
as x approaches 0.

I only know the basics so please explain.
Wolfram Alpha can calculate that for you:
http://www.wolframalpha.com/input/?i=cos%28x%29/%28%28e%5Ex%29-1%2B1%29+limit+-%3E+0
You can solve it by simple substitution. cos(0) = 1, e^0 = 1, and -1+1=0. That leaves you with 1/(1-1+1) = 1.
My mistake Kerm. Can you go to number 74 on this website:

http://www.aatm.org/pdf/State_Test_2009wa.pdf
Simple substitution now results in division by zero. Fortunately, the problem is just asking what value you can draw infinitely towards as x approaches 0. It can be done intuitively in this case, and Kerm's post is enough of a hint towards the solution.
If I may offer an additional hint in case you're still stuck (spoiler alert): L'Hopital's rule.

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