I've gotten all of my calc homework done except for one problem. We're trying to find the limit.
X^(1/4) - 8^(1/4)
---------------------
X^(1/2) - 8^(1/2)
X -> 8
I'm not sure what to do with this one. I probably just have to multiply by the conjugate, but what is X^(1/4) * X^(1/2)?
foamy3 wrote:
what is X^(1/4) * X^(1/2)?
X^(3/4).
You probably don't need this anymore, but just in case, here ya go...
The bottom can be factored as a difference of squares, so it would become
X^(1/4) - 8^(1/4)
-------------------------------------------------
(X^(1/4) - 8^(1/4)) * (X^(1/4) + 8^(1/4))
Then you just cancel and you are left with
1
-----------------------
X^(1/4) + 8^(1/4)
Then just replace X with 8 and bam, you've got your answer
Yeah, I got it, but thanks. I should have updated this.
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